Following is a regression equation.Y’ = 17.08 + 0.16X This information is also available: se= 4.05,

Following is a regression equation.Y’ = 17.08 + 0.16X This information is also available: se= 4.05, X = 210, = 1030, and n = 5.a.Estimate the value of Y’ when X = 50. (Round the final answer to 2 decimal places.) Y’ = b.Develop a 95% prediction interval for an individual value of Y for X = 50.

 

Looking for a Similar Assignment? Let us take care of your classwork while you enjoy your free time! All papers are written from scratch and are 100% Original. Try us today!